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AJAX PHP无刷新form表单提交的简单实现(推荐)
2016年11月05日

ajax.php：

<head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <script language="javascript"> function saveUserInfo() { //获取接受返回信息层 var msg = document.getElementByIdx_x("msg"); //获取表单对象和用户信息值 var f = document.user_info; var userName = f.user_name.value; var userAge = f.user_age.value; var userSex = f.user_sex.value; //接收表单的URL地址 var url = "./ajax_output.php"; //需要POST的值，把每个变量都通过&来联接 var postStr = "user_name="+ userName +"&user_age="+ userAge +"&user_sex="+ userSex; //实例化Ajax //var ajax = InitAjax(); var ajax = false; //开始初始化XMLHttpRequest对象 if(window.XMLHttpRequest) { //Mozilla 浏览器 ajax = new XMLHttpRequest(); if (ajax.overrideMimeType) {//设置MiME类别 ajax.overrideMimeType("text/xml"); } } else if (window.ActiveXObject) { // IE浏览器 try { ajax = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { ajax = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} } } if (!ajax) { // 异常，创建对象实例失败 window.alert("不能创建XMLHttpRequest对象实例."); return false; } //通过Post方式打开连接 ajax.open("POST", url, true); //定义传输的文件HTTP头信息 ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); //发送POST数据 ajax.send(postStr); //获取执行状态 ajax.onreadystatechange = function() { //如果执行状态成功，那么就把返回信息写到指定的层里 if (ajax.readyState == 4 && ajax.status == 200) { msg.innerHTML = ajax.responseText; } } alert (userName); } </script> <body > <div></div> <form name="user_info" method="post" action=""> 姓名：<input type="text"name="user_name" /><br /> 年龄：<input type="text" name="user_age" /><br /> 性别：<input type="text" name="user_sex" /><br /> <input type="button" value="提交表单" onClick="saveUserInfo()"> </form> </body>

 ajax_output.php：

<?php $username = $_POST['user_name']; $userage = $_POST['user_age']; $usersex = $_POST['user_sex']; echo "$username <br>"; echo "$userage <br>"; echo "$usersex <br>"; $db = new mysqli('localhost','root','123456','test'); if(!$db){ echo "连接失败！"; } $db->query("set names utf8"); $query = "insert into userinfo(uname,uage,usex) values ('".$username."','".$userage."','".$usersex."')"; $result = $db->query($query); if ($result){ echo "上传成功！"; } else { echo "失败！"; } $db->close(); ?>
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